8x^2+((4)(x^2-1))=0

Solution for 8x^2+((4)(x^2-1))=0 equation:

Simplifying
8x2 + ((4)(x2 + -1)) = 0

Reorder the terms:
8x2 + (4(-1 + x2)) = 0
8x2 + ((-1 * 4 + x2 * 4)) = 0
8x2 + ((-4 + 4x2)) = 0
8x2 + (-4 + 4x2) = 0

Remove parenthesis around (-4 + 4x2)
8x2 + -4 + 4x2 = 0

Reorder the terms:
-4 + 8x2 + 4x2 = 0

Combine like terms: 8x2 + 4x2 = 12x2
-4 + 12x2 = 0

Solving
-4 + 12x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 12x2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + 12x2 = 0 + 4
12x2 = 0 + 4

Combine like terms: 0 + 4 = 4
12x2 = 4

Divide each side by '12'.
x2 = 0.3333333333

Simplifying
x2 = 0.3333333333

Take the square root of each side:
x = {-0.577350269, 0.577350269}